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2 years ago

Which of the following ordered pairs lies on the graph of h(x)=-3x^2?

Mathematics

2 answers:

mel-nik [20]2 years ago

7 0

Answer:

None

Step-by-step explanation:

We are given that a graph $h(x)=-3x^2$

We have to find that which pair lie on the given graph.

In order to find the value of ordered pair which lies on the given graph by substituting the value of x=1

If we get h(x)=-4 or -2 or 4 corresponding to x=1 then that pair will be answer.

Substitute x=1 then we get

$h(x)=-3(1)^2=-3$

The order pair is (1,-3).

Given options do not match with order pair (1,-3).

Hence, answer is none of the above.

photoshop1234 [79]2 years ago

7 0

given, y= -2x^2;

so, when x=1, y= -2((1)^2)= -2

so pair which lie on graph is (x,y) is (1,-2)

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In Rivertown High School, about 30% of the students buy a raffle ticket. Given that a student buys a raffle ticket, there is a 1

lesya [120]

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

Step-by-step explanation:

Step 1 :

Given,

The percentage of students buying the raffle ticket = 30%

The percentage that the student who bought the ticket wins the prize = 10%

We need to determined the probability that randomly selected student will buy a raffle ticket and win a prize.

Step 2 :

The probability that a student buys the raffle ticket = $\frac{30}{100} = \frac{3}{10}$

The probability that a student wins a prize = $\frac{10}{100}$ = $\frac{1}{10}$

The probability that a student who buys the ticket wins a price can be computed by taking the product of the above 2 probabilities.

= $\frac{3}{10}$ × $\frac{1}{10}$ = $\frac{3}{100}$ = 0.03

Step 3 :

Answer :

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

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3 years ago

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zmey [24]

Answer:

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2 years ago

What is the correct classification of 18x?. . A.. monomial. . B.. binomial.. C.. trinomial.

kaheart [24]

By definition we have to:
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3 years ago

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Solutions

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2 years ago

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PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

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