U se the midpoint formula to find the midpoint of the line segment.
(5/2,5) or (5,5/2) it’s one of them .gotta be I’m pretty sure it’s (5/2,5)
Answer:
3=-8y+5
Step-by-step explanation:
Gather your like terms, - 3y and - 5y which in turn in - 8y. You cant plus by 5 as it is not a like term. IF we were finding y we would rearrange and bring +5 to the other side and so on...
Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
I think number 2 not sure tho