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3 years ago

10

HELP ME ASAPPPPPP !!!!!!! Picture attached

1 answer:

cricket20 [7]3 years ago

7 0

The answer is 7 good luck

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SOLVING SYSTEMS OF EQUATIONS BY SUBSTITUTION.<br><br> 1. 2x+3y=1<br> -3x+y=15

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$2x+3y=1 \\
-3x+y=15 \\ \\
\hbox{from the 2nd equation:} \\
-3x+y=15 \\
y=15+3x \\ \\
\hbox{substitute 15+3x for y in the 1st equation:} \\
2x+3(15+3x)=1 \\
2x+45+9x=1 \\
9x+2x=1-45 \\
11x=-44 \\
x=-4 \\ \\
\hbox{solve one of the equations for y}: \\
2x+3y=1 \\
2 \cdot (-4) + 3y=1 \\
-8+3y=1 \\
3y=1+8 \\
3y=9 \\
y=3 \\ \\
\hbox{the answer:} \\
x=-4 \\
y=3$

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