16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.
The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.
The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
Answer:

Step-by-step explanation:
To write the quadratic in standard form, begin by writing it in vertex form

Where (h,k) is the vertex of the parabola.
Here the vertex is (-3,-2). Substitute and write:

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

The vertex form of the equation is
.
To write in standard form, convert vertex form through the distributive property.

Answer:I got 9.85 hope it helps
.12 * $355 = $42.60. That is his discount.