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butalik [34]
3 years ago
11

What is this math problem x²+9×+14=0

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0
x^2+9x+14=0\\\\ x_{1}=\frac{-b-\sqrt{b^2-4ac} }{2a}=\frac{-9-\sqrt{9^2-4*1*14 } }{2 }=\frac{-9-\sqrt{81-56 } }{2 }= \frac{-9-\sqrt{25 } }{2 }=\\\\=\frac{-9-5 }{2 }=\frac{-14 }{2 }= -7\\\\ x_{2}=\frac{-b+\sqrt{b^2-4ac} }{2a}=\frac{-9+\sqrt{9^2-4*1*14 } }{2 }= \frac{-9+5 }{2 }=\frac{- 4 }{2 }= -2


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Nydia bought 1 pizza plus 2 toppings from Papa John's for $11. Ivan bought
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Answer:

1.25 Per topping

Step-by-step explanation:

First I looked at nydia and saw she bought 1 pizza just like Ivan but she bought 2 toppings Ivan bought 5 so i subtracted 11$ from 14.75$ and got 3.75$ and i divided that by 3 and got<u> 1.25$</u>

7 0
3 years ago
Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
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|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
2 years ago
What is the slope intercept form of the linear equation that passes through the point (0, 9) and has a slope of -6?
STALIN [3.7K]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

5mph

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Since both cars are travelling in the same direction,

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=56-48 =8mph

To catch the I car, the second car has to travel a distance of 40 miles extra in the same time as the I car

i.e. speed to be made up by the second car = 40 miles

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Hence time taken to catch up = \frac{40}{8} =5mph

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