What figure can be made using the net shown?

Mathematics

1 answer:

andrew-mc [135]3 years ago

5 0

Answer:

Hi, there it is rectangular pyramid

Step-by-step explanation:

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Write the numerical expression. 6 times the sum of 12 and 8. Write your answer with no spaces.

Murljashka [212]

Answer:

6(12+8)

Step-by-step explanation:

the word 'times' would indicate the multiplication of 2 numbers

the word 'sum' would indicate the addition of 2 numbers. in this case, 12 + 8 would be placed in parenthesis

hope this helps!! :)

7 0

3 years ago

Order this starting from the smallest:

lara31 [8.8K]

I think it might be easier to understand if i change decimals to fractions, so lets start ;)
$15.249=15\frac{249}{1000}$
$15.3=15.300=15\frac{300}{1000}$
$15.05=15.050=15\frac{50}{1000}$
$15.009=15\frac{9}{1000}$
$15.25=15.250=15\frac{250}{1000}$

denominators are the same so now you only have to compare numerators (biger numerator = greater fraction)

so:

$15\frac{9}{1000}$

it means that:

$15.009$

4 0

3 years ago

Read 2 more answers

What is the expression of this problem (9+6x)8

katrin [286]

Answer: You did not include the answer to the equation so 48x+72 is the closet I could get to finding the expression

Hope this Helped!!!

4 0

3 years ago

What are the solutions of the quadratic equation 49x^2=9?

Flauer [41]

<span>Simplifying 49x^2 + -9 = 0
Reorder the terms: -9 + 49x^2 = 0
Solving -9 + 49x^2 = 0 Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '9' to each side of the equation. -9 + 9 + 49x^2 = 0 + 9
Combine like terms: -9 + 9 = 0 0 + 49x^2 = 0 + 9 49x^2 = 0 + 9
Combine like terms: 0 + 9 = 9 49x^2 = 9
Divide each side by '49'. x^2 = 0.1836734694
Simplifying x^2 = 0.1836734694
Take the square root of each side: x = {-0.428571429, 0.428571429}

hope this helps!!</span>

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3 years ago

What step of the design process is this: “Used the test results to identify any modifications that they needed to make to improv

sergiy2304 [10]

I dont know how to answer this question

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3 years ago