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Alex17521 [72]
3 years ago
14

(Geometry) PLZ HELP ASAP

Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

<em>The height of the cylinder 'h' = 4 inches</em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

<em>Given diameter  of the cylinder ' d' = 10 inches</em>

 Diameter  of the cylinder    <em>d  = 2 r </em>

<em>Radius of the cylinder </em>

<em>                               </em>r = \frac{d}{2} = \frac{10}{2} = 5

Given Volume of the cylinder 'V' = 314 cubic inches

<em>Volume of the cylinder Formula</em>

<em>                                       V = π r² h</em>

                                  3 14  = 3.14 (5)² h

                                 h = \frac{314}{3.14 X 25}

                              <em>  h =  4</em>

<em>The height of the cylinder 'h' = 4 inches</em>

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Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
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I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
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What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

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