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3 years ago

13

IF A SUBSCRIPTION IS $499 PLUS 8% TAX FOR 30 DAYS, BUT IS BEING PRORATED FOR 7 DAYS, PLUS THERE IS A $10 OFF COUPON, WHAT'S THE

FINAL COST?

2 answers:

ELEN [110]3 years ago

5 0

Answer:

Your final answer is $528.92

Step-by-step explanation:

$499 + 8\% = 538.92$

$538.92 - 10 = 528.92$

Radda [10]3 years ago

5 0

Answer:

$519.6048

Step-by-step explanation:

Cost of subscription is $499 + 8% tax for 30 days

Cost of subscription for 30 days = $499

Cost of subscription for 1 days = $\frac{499}{30}$

So, Cost for (30-7 = 23)days = $\frac{499}{30} \times 23$

= $382.56$

Cost of subscription for 23 days = $382.56$

Sale tax = 8 %

Sales Tax = $30.6048$

Cost of subscription = $499+$30.6048 = $529.6048

There is an off of $10

So, Final cost = $529.6048-$10= $519.6048

Hence The final cost is $519.6048

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The volume of the cylinder is 84 pi inches squared What can be concluded about the volume of the cone? Check all that apply.

Zanzabum

Answer:

I dont know sorry

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help again.lol

Monica [59]

Answer:

$13\ units$

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

Where ( $(x_1,y_1)$ ) and ( $(x_2,y_2)$ ) are the points which one needs to find the distance between. In this case, these points are as follows:

$k\ (-3,5)$

$j\ (-8, -7)$

Substitute these points into the formula and solve for the distance between these points,

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

Simplify,

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

$D=\sqrt{(-3+8)^2+(5+7)^2$

$D=\sqrt{(5)^2+(12)^2$

$D=\sqrt{25+144}$

$D=\sqrt{169}$

$D=13$

8 0

2 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

Pls look i math pic i put and answer fast plssss i will mark u as brainliest

Lera25 [3.4K]

Answer:it’s 80ft hope this helps

Step-by-step explanation:

8 0

3 years ago

Answer and explain ILL MARK BRAINLIEST I DONT UNDERSTAND

Sati [7]

First let's reduce the feet to miles

there are 5280 feet in a mile therefore

26400 feet=5 miles

31680 feet=6 miles

Jet A(the first jet) descends 5 miles in 96 miles

Jet B(the second jet) descends 6 miles in 120 miles

We can compare these as fractions to see which is steeper. This can be viewed as slope and the origin (0,0) is the airport.

slope: 6/120=?=5/96

1/20=?=5/96

Now we know that 5/100 =1/20 so 5/96 must be bigger than 5/100 because you are dividing by a smaller number.

so 1/20<5/96

So Jet B is descending steeper than Jet A.

As for linear model, I don't exactly know what your teacher means but I think I actually used the linear model when I'm thinking of steepness as slope in the coordinate plane, I will include a picture.

In this extremely zoomed out graph, you can see the blue line is just slighly higher than the red line(slope as in explanation is way easier to tell) this could be seen as the linear model) :) Hope it helped!

6 0

2 years ago