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Gre4nikov [31]
2 years ago
8

What is the value of -2.12 - 6.84 + 4.19?

Mathematics
1 answer:
hodyreva [135]2 years ago
8 0

Answer:

Try 8.91

Step-by-step explanation:

6.84+4.19=11.03-2.12=8.91

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What is the effect on the graph of the function f(x) = 2^x when f(x) is replaced with f(x − 3)?
mel-nik [20]

Graph of f(x-3) is compressed by a factor of  \frac{1}{8} horizontally of f(x).

<u>Step-by-step explanation:</u>

We have, the graph of f(x)= 2^{x} , on replacing f(x) by f(x-3) we get:

f(x-3)= 2^{x-3} = \frac{2^{x}}{2^{3}} = \frac{1}{8} 2^{x} = \frac{1}{8} f(x).Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of  \frac{1}{8} horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : f(x-3) = \frac{1}{8} f(x).

4 0
3 years ago
Can I PLEASE get some help?
Leviafan [203]
Well 1/40 is 0.025 so that should be the write fraction to use
4 0
3 years ago
Read 2 more answers
The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi
eimsori [14]

Answer:

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=4.2 represent the sample mean  

s=1.4 represent the sample standard deviation  

n=16 represent the sample selected  

\alpha=0.05 significance level  

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:    

Null hypothesis:\mu = 3.6    

Alternative hypothesis:\mu \neq 3.6    

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with df=n-1=16-1=15 degrees of freedom. The value for \alpha=0.05 and \alpha/2=0.025 so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got t_{crit}=\pm 2.131    

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

Conclusion    

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0
3 years ago
Dorian buys 2 pounds of almonds for $21.98 and 3 pounds of dried apricots for $26.25. Which is less expensive per pound? How muc
ozzi

Answer:

The apricots are less expensive per pound.

Step-by-step explanation:

Cost of 1 pound of almonds = 21.98/2

Cost of 2 pounds of almonds = $21.98

So then you have to do 21.98 - 21.98/2. Which equals $10.99

Cost of 1 pound of dried apricots = 26.25/3

Cost of 3 pounds of dried apricots = $26.25

So then you have to do $26.25 - 26.25/3 which = $17.5 then divide that by 2 which equals $8.75.

To find out how much less expensive you have to find the difference, so to do that you have to do $10.99 - $8.75 = $2.24 per pound less expensive.

4 0
3 years ago
») Evaluate the expression for c = 4 and d = 11.<br> C + d =
HACTEHA [7]

Answer:

4+11=15

Step-by-step explanation:

c=4 11=b

4(c) + 11(d) = 15

8 0
2 years ago
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