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borishaifa [10]
2 years ago
10

Simplify (2z^5)(12z^3)/4z^4

Mathematics
1 answer:
Sphinxa [80]2 years ago
5 0

Answer:

6z^{4}

Step-by-step explanation:

Given in the question an expression,

\frac{ (2z^5)(12z^3)}{4z^4}

Step 1

Apply exponential "product rule"

x^{m}x^{n}=x^{m+n}

\frac{ 12(2)z^5)(z^3)}{4z^4}

\frac{ (24)z^5)(z^3)}{4z^4}

\frac{ 24(z^{(5+3)})}{4z^4}

\frac{ 24(z^{8})}{4z^4}

Step 2

Apply exponential " divide rule"

\frac{x^{m}}{x^{n}}=x^{m-n}

\frac{24/4(z^{8})}{z^4}

\frac{6(z^{8})}{z^4}

\frac{6(z^{8-4})}{1}

6z^{4}

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Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

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FinnZ [79.3K]
<h3>Answer: Choice A</h3>

The first line shown in choice A is a_1 = -2 which means "the first term is -2"

The next line in choice A means "the nth term (a_n) is found by multiplying the prior term (a_{n-1}) by 8". Put another way: multiply each term by 8 to get the next term.

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fourth term = 8*(third term) = 8*(-128) = -1024

and so on.

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