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3 years ago

11w +99 < 33 algebra answer

Mathematics

2 answers:

Otrada [13]3 years ago

3 0

Answer:

w<-6

Step-by-step explanation:

11w+99<33

-99

11w<-66/11

PolarNik [594]3 years ago

3 0

Answer:

w < -6

Step-by-step explanation:

Step 1: Subtract 99 from both sides.

11w + 99 − 99 < 33 − 99

11w<−66

Step 2: Divide both sides by 11.

$\frac{11w}{11} < \frac{-66}{11}$

Answer:

w < -6

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nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

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We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

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So, $P(D)=\frac{1}{10000}$

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(B)

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