About the same as the previous posting
a = gallons used up by the 20 mpg car
b = gallons used up by the 30 mpg car
we know on that week they both consumed 65 gallons altogether, therefore
a + b = 65.
we also know that they did a combined mileage of 1550. Now, in 1 gallon the 20mpg car does 20(1) miles, in 2 it does 20(2) miles, in 3 gallons it does 20(3) and in "a" it does 20(a) or
20a miles.
likewise, the 30mpg car does 30(b) in b gallons, or
30b miles.
Therefore,
20a + 30b = 1550.

how many gallons is it consumed by the 30mpg car? well b = 65 - a.
You've already completed the first step by lining up terms with the same variables. Like addition, simply add them together column by column. x+(-x) equals 0 so it is cancelled out. 4y plus 6y is 10y. 9+11=20. We are left with 10y equals 20, so y equals 2. Then plug in the y value into either equation. I will use the first so x +4(2)=9. x must equal 1. Double check by plugging in both x and y into the second equation.
(8xn)+6 would be your equation. please mark me as brainiest.
Answer:
(3,3)
Step-by-step explanation:
x + y - 6= 0
x- y = 0
Add the two equations together
x + y - 6= 0
x- y = 0
-------------------
2x - 6 = 0
Add 6 to each side
2x-6+6 = 0
2x = 6
Divide by 2
2x/2 = 6/2
x = 3
Now find y
x-y = 0
3 - y = 0
y = 3
The answer is 2x-1
Step-by-step explanation:
2x-10^0
Any non zero expression raised to the power of 0 equals 1.
2x-1
So that would be your answer.
Hope that helped.