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3 years ago

HTTP is made to facilitate which kind of communication?

1 answer:

4 0

HTTP is also used as a generic protocol for communication between user agents and proxies/gateways to other Internet systems, including those supported by ...

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

The file type blank identifies a word 2013 document

ZanzabumX [31]

Hey there! Hello!

The exclusive file type for Microsoft Word documents is .docx. You can see the attachment showing all the information you need to know about the example Word document I created. As long as you are using Word, the file type will be the same no matter what type of computer you're on or what it's running, so you don't need to worry about it being different for me on Mac than it might be for you on Windows.

Hope this helped you out! Feel free to ask me any additional questions you may have. :-)

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3 years ago

Which statement about dialogues is NOT correct? Select one: A. Users should be able to control the direction of speed of dialogu

Gennadij [26K]

Answer:

Option B is not correct

Explanation:

Dialogues become problematic when they appear automatically because of high level incompatibility

3 0

2 years ago

Can you make a phone app with angular?.

emmainna [20.7K]

Answer:

yes

Explanation:

4 0

2 years ago

c++ Write a statement that increments (adds 1 to) one and only one of these five variables: reverseDrivers parkedDrivers slowDri

Mazyrski [523]

Answer:

The following statement are:

if(speed < 0) // if statement

{

reverseDrivers++; //if the speed is less than 0, then increment in "reverseDrivers"

}

else if(speed < 1) //else if statement

{

parkedDrivers++; //speed is less than 1, than increments in "parkedDrivers"

}

else if(speed < 40)

{

slowDrivers++; //speed is less then 40, than increment in "slowDriver"

}

else if(speed <= 65)

{

safeDrivers++; //speed is less than or equal to 40, then increment in "safeDriver"

}

else

{

speeders++; //else increment in speeders

}

Explanation:

From the following statement their are certain condition arises

If the speed is less than 0, then increments the “reverseDrivers” variable by 1.

If the speed is less than 1, then increments the “parkDriver” variable by 1.

If speed is less than 40, then increment in "slowDriver" variable by 1.

If speed is less than or equal to 40, then increment in "safeDriver" variable by 1.

Otherwise increment in "speeders"

7 0

2 years ago