1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
suter [353]
3 years ago
7

PLEASE HELP ILL REWARD A LOT

Mathematics
2 answers:
marin [14]3 years ago
7 0
23.10oz i dont have explanation but its can speaks for it selfs
aev [14]3 years ago
5 0

Answer:

-1 and 10

Step-by-step explanation:

x2-9x-10

=x2-10x+x-10=0

=x(x-10)+1(x-10)

=(x+1)(x-10)

=x=-1,10

You might be interested in
Solve this pleasee!!!!!!!!!!!
Sholpan [36]

Answer:

1) Solution (2,-3)

2) Solution (-1, -\frac{3}{2})

3) Solution (\mathbf{-\frac{1}{2},-\frac{5}{2}})

Step-by-step explanation:

We need to solve equations using elimination

1) 2x+2y=-2\\3x-2y=12

Let:

2x+2y=-2--eq(1)\\3x-2y=12--eq(2)

Adding both equations:

2x+2y=-2\\3x-2y=12\\--------\\5x=10\\x=\frac{10}{5}\\x=2

We get value of x = 2

Now, put value of x into equation 1 to find value of y

2x+2y=-2\\Put\:x=2\\2(2)+2y=-2\\4+2y=-2\\2y=-2-4\\2y=-6\\y=-6/2\\y=-3

So, we get y = -3

Solution (2,-3)

2) 4x-2y=-1\\-4x+4y=-2

Let:

4x-2y=-1--eq(1)\\-4x+4y=-2--eq(2)

Adding both equations

4x-2y=-1\\-4x+4y=-2\\------\\2y=-3\\y=\frac{-3}{2}

We get: y= -3/2

Now find value of x by putting value of y in eq(1)

4x-2y=-1\\Put\:y=\frac{-3}{2}\\4x-2( \frac{-3}{2})=-1\\4x+3=-1\\4x=-1-3\\4x=-4\\x=\frac{-4}{4}\\x=-1

We get x = -1

Solution (-1, -\frac{3}{2})

3) x-y=2\\x+y=-3

let:

x-y=2--eq(1)\\x+y=-3--eq(2)

Add both equations:

x-y=2\\x+y=-3\\-----\\2x=-1\\x=-\frac{1}{2}

We get x = -1/2

Now, put value of x in equation 2

x+y=-3\\-\frac{1}{2}+y=-3\\y=-3+ \frac{1}{2}\\y=\frac{-6+1}{2}\\y=\frac{-5}{2}

We get y = -5/2

Solution (\mathbf{-\frac{1}{2},-\frac{5}{2}})

7 0
3 years ago
4xy(x cubed +5xy- 7y squared)
VARVARA [1.3K]

Answer:

4x^4y + 20x^2y^2 - 28x^3y

Step-by-step explanation:

4xy(x^3 + 5xy - 7x^2)

= 4xyx^3 + 4xy * 5xy - 4xy * 7x^2

= 4x^2y + 4xy * 5xy - 4xy * 7x^2

= 4x^4y + 20x^2y^2 - 4xy * 7x^2

= 4x^4y + 20x^2y^2 - 28x^3y

4 0
4 years ago
Read 2 more answers
1/2 of 4/5=1/2 of ___ fifth(s) = ___ fifth(s)
barxatty [35]

Answer:

1/2 of 4/5 = 1/2 of four fifths = two fifths

Step-by-step explanation:

1/2 x 4/5 = 4/10

4/10 simplified is 2/5

4 divided by 2 = 2

----                      ----

10 divided by 2= 5

3 0
3 years ago
Read 2 more answers
Find the area of the shaded region in the figure below.
Inessa [10]
I think the answer is D
5 0
3 years ago
Read 2 more answers
Explain why a polar curve is not always bounded.
Scrat [10]

Answer: There are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. A polar curve is required to have an unbounded function (right side of r = f(Θ)) to be an unbounded polar. An example of an unbounded curve would be r = Θ for 0 ≤ Θ.

8 0
3 years ago
Other questions:
  • A random sample of n measurements was selected from a population with unknown mean μ and known standard deviation σ. Calculate a
    9·2 answers
  • A number decreased by 1/3 of itself
    5·1 answer
  • How many zero pairs must be added to the function
    10·2 answers
  • It’s kinda urgent lol
    9·1 answer
  • From a group of 20 day workers and 12 night workers, a skeleton work crew of 5 day workers and 3 night workers must be formed. i
    10·1 answer
  • Ms. Alvarez has 1,482 to spend on origami paper . How many packs can she buy
    11·1 answer
  • The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i
    11·1 answer
  • Evaluate the expression. 32 ÷ 8 · 4
    13·2 answers
  • The slope of a line is 7/10 . One point on the line has coordinates (1, 2). Which ordered pair represents another point on the l
    14·1 answer
  • Evaluate (98 x 102) by using suitable identities.
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!