All categories

3 years ago

PLEASE HELP ILL REWARD A LOT

Mathematics

2 answers:

marin [14]3 years ago

7 0

23.10oz i dont have explanation but its can speaks for it selfs

aev [14]3 years ago

5 0

Answer:

-1 and 10

Step-by-step explanation:

x2-9x-10

=x2-10x+x-10=0

=x(x-10)+1(x-10)

=(x+1)(x-10)

=x=-1,10

You might be interested in

3.Write the product as a trinomial. (2r – 5)(r + 10)

Maurinko [17]

B is the correct answer

5 0

3 years ago

Read 2 more answers

Find the real zeros of f(x); there are 4 zeros

ziro4ka [17]

Answer:

x = 4 or x = 1 or x = -2 or x = -3/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^4 - 3 x^3 - 21 x^2 - 2 x + 24 = 0

The left hand side factors into a product with four terms:

(x - 4) (x - 1) (x + 2) (2 x + 3) = 0

Split into four equations:

x - 4 = 0 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 4 to both sides:

x = 4 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 1 to both sides:

x = 4 or x = 1 or x + 2 = 0 or 2 x + 3 = 0

Subtract 2 from both sides:

x = 4 or x = 1 or x = -2 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 4 or x = 1 or x = -2 or 2 x = -3

Divide both sides by 2:

Answer: x = 4 or x = 1 or x = -2 or x = -3/2

7 0

3 years ago

Read 2 more answers

1 (15 Points]. Prove the following statement: is divisible by 3 if only if it is a sum of three consecutive integers. be ddvisbk

Alinara [238K]

Answer:

<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.

Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:

n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).

So, n can be written as 3 times another integer, thus n is divisible by 3.

<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.

Assume that n is divisible by 3. The above proof suggest that we write it as

n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).

As k, k+1, k+2 are three consecutive integers, we have completed our goal.

Step-by-step explanation:

4 0

3 years ago

What is the volume of a cone that has a radius of 4 cm and a height of 9 cm?

vodka [1.7K]

For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is $V=Bh$ , the volume of a pyramid/cone is $V=\frac{1}3Bh$ .

In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is $A=\pi r^2$ where r is the radius.
$A=\pi (4)^2=\pi (4\times4)=16\pi=B$

We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.

$V=\frac{1}3\times16\pi \times9$

Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.

$V\approx\frac{1}3\times50.24\times9$

We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

$V\approx3\times50.24$

$\boxed{V\approx150.72\ cm^3}$

8 0

3 years ago

Read 2 more answers

Please give me the correct answer.Only answer if you're very good at math.

GaryK [48]

Answer:

-9 = 0.45m

Step-by-step explanation:

$0.45m - 9 = 0.9m$

^ Subtract 0.45m from BOTH sides. so $0.9m - 0.45m$ ... etc
Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
That will equal to:

$-9 = 0.45m$ <-- ANSWER

3 0

3 years ago

Read 2 more answers