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MAXImum [283]
2 years ago
11

Writing lan's car can go 217 miles on 7 gallons of gas. During a drive last weekend, lan used

Mathematics
1 answer:
jolli1 [7]2 years ago
3 0

Answer: Ian would have drove 91 miles using only 3 gallons of gas.

Step-by-step explanation: I used paper and pencil and used a T-chart putting one section at the top “gallons” and the other “miles”; under gallons I put 7 because the question stated with “7 gallons of gas”; under miles I put 217 because the question states that with 7 gallons of gas Ian’s car travels 217 miles so using the T-chart I want to simply the 7 gallons of gas to one gallon of gas to figure out how miles Ian’s car would go only using 3 gallons of gas; by dividing 7 by 7 giving me 1, and with a T-chart you wanna do the same thing to both sides meaning I divided 217 by 7 as well giving me 31 for 1 gallon of gas, meaning Ian’s car would travel 31 miles with only using 1 gallon of gas. After I find that answer I go to multiply the 1 under “gallons” by 3 to and again, if you do it to one side you have to do it to the other meaning I multiplied 31 my 3 as well; giving me 91. Meaning with only using 3 gallons of gas Ian’s car would travel 91 miles!

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LiRa [457]

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<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

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__

<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

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The GCF is 1/63.

__

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

_____

<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

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