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3 years ago

Tyra solves the equation as shown.

Mathematics

1 answer:

torisob [31]3 years ago

5 0

Answer:

D…

Step-by-step explanation:

Yours^(I can’t)

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One-third of 2c subtracted from five times nine

SOVA2 [1]

One-third of 2c subtracted from five times nine
1/3 of 2c subtracted 5 x nine
1/3 x 2c - 5(9)
=1/3 x 2c - 45
=2c/3 - 45
if we solve for c,
2c/3 = 45
2c = 45 x 3
2c = 135
c = 135/2
c = 67.5

4 0

3 years ago

The volume V of a gas varies inversely as the pressure P and directly as the temperature A certain gas has a volume of 10 liters

Ad libitum [116K]

Answer:

Joint variation states that:

If z is directly proportional to x and inversely proportional to y,

i.e, $z \propto x$ , $z \propto \frac{1}{y}$

then the equation is in the form: $z = k\frac{x}{y}$ where k is the constant of variation.

From the given information: The volume V of a gas varies inversely as the pressure P and directly as the temperature

i.,e $V \propto T$ , $V \propto \frac{1}{P}$

by definition of joint variation:

$V = k\frac{T}{P}$ .....[1] where k is the constant of variation.

It is also given that a certain gas has a volume of 10 liters(L) , a temperature of 300 kelvins(K), and a pressure of 1.5 atmosphere(atm).

Substitute these given values in [1] to solve for k;

$10 = k\frac{300}{1.5}$

Simplify:

$10 = 200k$

Divide by 200 both sides we have;

$k = \frac{10}{200} =\frac{1}{20}$

Now, if a gas has a temperature of 400 kelvins and a pressure of 5 atm.

To find the volume (V);

Now substitute the given data and value of k in [1] we have;

$V = \frac{1}{20} \cdot \frac{400}{5} = \frac{20}{5} = 4$

Therefore, the Volume of a gas is, 4 liters

5 0

3 years ago

Please help me I need it now

drek231 [11]

Both x and y are positive

8 0

3 years ago

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50 points! I think the answer is B but I'm not sure!

eimsori [14]

Answer: B

Step-by-step explanation:

3 0

3 years ago

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Write the quadratic equation in general form and then choose the value of "b."

Ira Lisetskai [31]

First of all to transfer (2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.

(2x - 1)(x + 6) = 0
 becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - 6

now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - 6

a=2,b=11,and c=-6

4 0

4 years ago

Read 2 more answers