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Arturiano [62]
3 years ago
7

Pls help will give branilest

Mathematics
1 answer:
EleoNora [17]3 years ago
3 0
Hope this helps you

have a great day ^^

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Malcolm solves w2-3w=350​
stiv31 [10]

Answer:

20.26832436,-17.26832437

5 0
3 years ago
HELP ME OUTT PPL (BRAINIEST)
Annette [7]

Answer:

(0, 6)

Step-by-step explanation:

Point T is at (3, 4), and three units to the left would be (0, 4). They then tell us to go two points up, which would change the ordered pair to (0, 6).

I hope this was helpful! Have a lovely day! :D

3 0
2 years ago
Find the zeros of polynomial functions and solve polynomials equations.<br> f(x)=2x^3+2x^2-4x
vladimir2022 [97]

f(x)=2x^3+2x^2-4x

The zeros of polynomial functions

2x^3 + 2x^2 - 4x = 0

2x(x^2 + x - 2) = 0

2x(x - 1)(x + 2) = 0

2x = 0; x = 0

x - 1 = 0; x = 1

x + 2 = 0; x = -2

Answer

x = -2 , 0 , 1


4 0
4 years ago
Question 26 pleaseee
LuckyWell [14K]

Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

          Jeremy can spend no more than $105

Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

\$55+ \$ 10\times x

We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

\$ 55+\$10x\leq \$ 105

Now solving the inequality to find the greatest number of time Jeremy can rent the jet ski,

⇒ \$ 55+\$10x\leq \$105

Subtracting both side by 55

⇒ \$ 10x\leq \$50

Dividing both side by 10

⇒x\leq \frac{50}{10}

∴ x\leq 5

Therefore, Jeremy can rent for 60\ minutes + 5\times 15\\= 60\ minutes + 75= 135\ minutes

Jeremy can rent maximum of 135 minutes.

5 0
3 years ago
The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5

Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.

Hope this helps! :)
3 0
3 years ago
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