Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
Answer:
28 sixth graders will attend
Step-by-step explanation:
Answer:
The value of x is 25°.
Here is your solutions too.
P = $3,471.52, the principal
r = 3.1% = 0.031, annual ratr
n = 12, monthly compounding
t = 21 years
Note that n*t = 252.
The value after 21 years is
A = 3471.52*(1 + 0.031/12)²⁵²
= $6,650.91
The interest earned is
6650.91 - 3471.52 = 3179.39
Answer: $3,179.39
