The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
I think it would just be 13 because T to U is 11 and U to V is 2 so if you want to find T to V you would add them together
Hope this helps in any way :))
Answer:
8.15
Step-by-step explanation:
(2^2)^4 x 2^0 =
4^4 x 2^0 =
256 x 1 =
256
<u>Given</u>:
- Length of side of cube = 10m
<u>To Find</u>:
<u>Solution</u>:
Using formula:
Volume of cube= (10)³
Volume of cube = 10 × 10 × 10
Volume of cube = 1000 <u>m</u>³
Hence,
