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Andru [333]
3 years ago
14

In a large data set the 40th percentile is 125 and the 82nd percentile is 158. Approximately what percentage of observations lie

between 125 and 158
Mathematics
1 answer:
liq [111]3 years ago
3 0

Answer:

42% of observations lie between 125 and 158.

Step-by-step explanation:

Interpretation of a percentile

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Two values have a percentile, how many are between then?

In this example, y is larger than x.

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

When a value Z is said to be in the yth percentile of a set, y% of the values in the set are lower than V and (100-y)% of the values in the set are higher than V.

Also, (y-x)% of the values are between V and Z.

In this problem, we have that:

125 is the 40th percentile

158 is the 82nd percentile

Approximately what percentage of observations lie between 125 and 158

82 - 40 = 42% of observations lie between 125 and 158.

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Vesnalui [34]

3x - 1 = 3x + 1  

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4x - 11 = 7

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3 years ago
TUESDAY: Which of the following statements are true about quadratics? *
babymother [125]

Answer:

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3 0
3 years ago
A statistics professor drew a random sample of 81 observations and found that x with bar on top equals 62 s equals 15. Estimate
ratelena [41]

Answer:

LCL = 59.26 to two decimal places

Step-by-step explanation:

Here, we want to estimate the LCL of the population mean with 90% confidence

We proceed as follows;

Given alpha = 0.1, then Z(0.05)=1.645 (from standard normal table), s = 15

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3 0
3 years ago
Can someone please help me I really need help please help me
scZoUnD [109]

Answer:

18.87 square cm.

Step-by-step explanation:

The area of the rectangle will be (4 + 4) * 4, since the length of the rectangle would be the diameter of the circle, and the width of the rectangle would be the radius. (4 + 4) * 4 = 8 * 4 = 32 square cm.

Then, we can calculate the area of the semicircle. The area of a circle is pi * r^2, so the area of a semicircle will be half of that. pi * (4^2) / 2 = pi * 16 / 2 = 8pi. 8 * 3.14159265 = 25.1327412 square cm.

The shaded area of the middle of the shape will then be 32 - 25.1327412 = 6.8672588 square cm.

The two triangles will have the same area. Their bases will be 14 minus the diameter of the circle, then divide that by 2 to get each separate base. 14 - 8 = 6 / 2 = 3. The heights of the triangles will be the radius of the circle, or 4 cm.

1/2 * 3 * 4 = 1/2 * 12 = 12/2 = 6. That is the area of one triangle, so the area of both triangles would be 6 * 2 = 12 square cm.

6.8672588 + 12 = 18.8672588, or 18.87 square cm.

Hope this helps!

3 0
3 years ago
Read 2 more answers
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