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hammer [34]
3 years ago
7

What is the least common factor of 10 and 25?

Mathematics
2 answers:
topjm [15]3 years ago
8 0

Answer:

the answer is 5

Step-by-step explanation:

The least common factor of 10 and 25 is: 1. The HIGHEST common factor is 5, and the least common MULTIPLE is 50.

hope it helps

mark me brainliest pls

swat323 years ago
3 0
The best common factor of 10 and 25 are 5
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Suppose that an individual has a body fat percentage of 15.6 and weight 126 pounds. How many pounds of her weight is made up of
garri49 [273]

126(.156) = 19.66 pounds of fat

6 0
3 years ago
Why might the mean of a probability distribution for a discrete random variable be less than (or greater than) the average of po
user100 [1]

The Normal probability distribution function is left-skewed, right-skewed, or symmetric depending on the values of the variance and the standard deviation might the mean of a probability distribution for a discrete random variable be less than (or greater than) the average of possible values.

A probability distribution is a mathematical function that describes the probabilities of different possible values ​​of a variable. Probability distributions are often represented using graphs or probability tables.

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4 0
2 years ago
Consider that an = 4n-1 represents a sequence. What is the tenth term? A) 361 B) 512 C) 1,024 D) 4,096 E) 262,144
mel-nik [20]

Hello from MrBillDoesMath!

Answer:

Choice E.

Discussion:

Assuming that n >=1, a(n) = 4n -1, then

a(10) = 4(10) - 1 = 39    

but that doesn't match any of the answers...... hmm...

BUT

If you meant that a(n) = 4^(n-1),  then

a(10) = 4^(10-1) = 4^9 =  262144    

which is Choice E.

Thank you,

MrB

4 0
3 years ago
Help me fast please helpppp
ArbitrLikvidat [17]

8-x-10=2x+4-3x\\ -x+x=-2-4\\ 0=-6

so, no solutions

3 0
3 years ago
(3xy/3x^2-12)*(x^2+3x+2/xy+y)
TiliK225 [7]

Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

<u>Step-by-step explanation:</u>

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y)  or ,

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

Let's simplify this

⇒ (\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})

Factorizing the terms we get:

⇒ (\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})              { a^2-b^2=(a+b)(a-b)      }

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})

Cancelling similar terms we get:

⇒ \frac{x}{x-2}

Therefore , Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

3 0
3 years ago
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