Answer:
250
Step-by-step explanation:
245 / 0.98 = 250
Solution: 137 / 2 = 68.5
LMP is 11 degress more so 68.5 + 11 = 79.5
NMP is 11 degrees less so 68.5 - 11 = 57.5
Answer to a1=6.8
a2= 0.5
mean is 6.78
i don’t know the rest sorry
Given:
grams of fat : 34 grams TO weight of woman : 102 pounds
grams of fat : ? TO weight of woman : 180 pounds
This is a proportion problem: 34 grams to 102 pounds.
We first have to convert a unit of measure to another to maintain uniformity of measure. let us convert pounds to grams:
102 pounds * 453.592 grams / pound = 46,266.384 grams
180 pounds * 453.592 grams / pound = 81,646.560 grams
34 grams to 46,266.384 grams = x grams to 81,646.560 grams
proportion: a:b = c:d where ad = bc
34 grams * 81,646.560 grams = x * 46,266.384 grams
2,775,983.04 grams² = x * 46,266.384 grams
2,775,983.04 grams² ÷ 46,266.384 grams = x
60 grams = x
A woman weighing 180 pounds should eat 60 grams of fat to maintain her weight.
The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then




