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3 years ago

5c - 15 = 2c + 6 please help me solve it

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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On Monday, Jayla raised $30 and Carlos raised $50.

gayaneshka [121]

Answer:

84 days

Step-by-step explanation:

You would use the LCM to solve this.

12 and 7 don't share any common factors other than 1,

so you would multiply 12 x 7, which gets you 84.

After 84 days they would have raised the same amount.

8 0

4 years ago

Help me please by solving and showing the steps:)

Lorico [155]

Answer:

$-\frac{3\sqrt[3]{t} }{2}$

Step-by-step explanation:

1: Write g(t) as y, resulting in $y=-\frac{8}{27}t^3$

2: Interchange the variables y and t, resulting in $t=-\frac{8}{27}y^3$

3: Multiply both sides by 27, resulting in $27t=-8y^3$

4: Divide both sides by -8, resulting in $-\frac{27t}{8}=y^3$

5: Find the cube root of both sides, resulting in $\sqrt[3]{-\frac{27t}{8} }=y$

6: Apply a radical rule, resulting in $-\sqrt[3]{\frac{27t}{8} } =y$

7: Apply another radical rule, resulting in $-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y$

8: Simplify the denominator, resulting in $-\frac{\sqrt[3]{27t} }{2} =y$

9: Apply yet another radical rule, resulting in $-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y$

10: Simplify $\sqrt[3]{27}$ , resulting in $-\frac{3\sqrt[3]{t} }{2} =y$

3 0

3 years ago

Explain how you would graph 3x+9y= -18 without converting to slope-intercept form

Zolol [24]

Answer:

you would solve using x and y intercepts.

Step-by-step explanation:

for the X intercept, Y=0

3x=-18. you divide by three on both sides

x=-6. (-6,0)

the for the y intercept, X=0

+9y=-18. you divide 9 on both sides.

y=-2. (0,-2)

then you graph both and connect the points on the x and y axis.

Brainiest always accepted!!!!1

8 0

4 years ago

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

3 years ago

Read 2 more answers

Write each ratio in simplest form 3 in. to 2 ft

Degger [83]

$1ft=12in\to2ft=24in\\\\3in:2ft=3in:24in=3:24=\dfrac{3}{24}=\dfrac{3:3}{24:3}=\dfrac{1}{8}=1:8$

4 0

4 years ago