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Ierofanga [76]
2 years ago
5

Do you know the answer?

Mathematics
1 answer:
Anastaziya [24]2 years ago
3 0

Answer:

c

Step-by-step explanation:

no need to explain

hope it helps

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What is the value of x?<br> a . 75<br> b . 25.5<br> c . 8<br> d . 4.5<br><br> help meeee
Rashid [163]

Answer:

d. 4.5

Step-by-step explanation:

10x-5=16x+22

    -22      -22

10x-27=16x

-10x      -10x

-27=6x

x=4.5

3 0
2 years ago
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Joanne's bus was 27 minutes late tonight. She called to say she would be about a half hour late for dinner. Explain why this was
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This is correct, because it takes 27 minutes to get home so it will probably be about 30 minutes.
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3 years ago
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the length is 8cm???

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3 years ago
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Need help with trig
Sedaia [141]
SinA= 16/20= 4/5=0.8 degree
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5 0
2 years ago
Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of
IrinaK [193]
Recall that the characteristic polynomial of a 2x2 matrix \mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix} is

\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)

but \det(\mathbf A)=ad-bc and \mathrm{tr}(\mathbf A)=a+d, so the characteristic polynomial for \mathbf A is

\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

\lambda^2-15\lambda+50

and the eigenvalues are those \lambda for which the characteristic polynomial evaluates to 0.

\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10
5 0
2 years ago
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