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nika2105 [10]
3 years ago
13

What is the equation of a line perpendicular to 3X+6Y= -3 and passes through the points (1,-5)

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

Step-by-step explanation:

6y = -3x - 3

y = -1/2x - 1/2

perp. 2

y + 5 = 2(x - 1)

y + 5 = 2x - 2

y = 2x - 7

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What are the coordinates of a point in quadrant ||| which is 8 units away from point p Answer quick
trapecia [35]

Answer:

If it is at -8, -8 then p is at 0,0

Step-by-step explanation:

Sorry, there is not much information given to answer.

5 0
2 years ago
you took out a loan of $1,200 with the principal pay off of $200 a month each month you paid 200 plus the interest at a rate of
Bad White [126]
I think the answer you are looking for is $2,592
5 0
3 years ago
WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION<br> PLS ANSWER THIS TRIGONOMETRY QUESTION
mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

\theta=?

Relationship between opposite and adjacent is given by tan angle

so

Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}

Tan \theta=\frac{3}{4}

\theta=Tan^{-1}\frac{3}{4}

\bold{\theta=36.8°}

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

\theta=62°

Relationship between height and hypotenuse is given by Sin angle

:.

Sin 62°=\frac{opposite}{hypotenuse}=\frac{b}{11}

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°=\frac{base}{hypotenuse}=\frac{a}{11}

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>

4 0
2 years ago
Which of the following vectors are orthogonal to (1,5)? Check all that apply
Andre45 [30]
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal

</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal 

</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are  orthogonal 

<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal 

<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are  orthogonal 

the answer is 
B. (10,-2) and D. (-5,1)  are  orthogonal  to  (1,5)
7 0
2 years ago
If the integral of f(x)dx = 2.3 from 1 to 3 and F'(x) = f(x), what is the value of F(3) - F(0). The graph will be inserted as a
lana66690 [7]
<span>F(3)−F(0)=<span>∫30</span>f(x)dx</span><span>
so it looks like 2.3+1=3.3</span>
4 0
3 years ago
Read 2 more answers
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