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3 years ago

Select the correct answer.

Mathematics

1 answer:

pochemuha3 years ago

8 0

30y-27 I believe, but there's no options

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Add the opposite of 2.5 to the sum of 1.25 and (−1.75 ).

Bezzdna [24]

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▹ Answer

▹ Step-by-Step Explanation

1.25 + (-1.75) = -0.5

Opposite of 2.5 = -2.5

-2.5 + (-0.5) = -3

Hope this helps!

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3 0

3 years ago

Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr

prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

$[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]$

Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

$\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4$

$=\displaystyle\sum_{i=1}^4\frac{\left(\frac{i-1}2\right)^2+\left(\frac i2\right)^2}4=\frac{11}4$

4 0

3 years ago

How to solve 243.6divided by 8

OLga [1]

Answer:

the answer is 30.45

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the average rate of change between (3,2) and (1,9)

hjlf

Answer:

-0.25

Step-by-step explanation:

1-3= -2

9-2= 8

-2/8= -0.25

7 0

3 years ago

If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution

FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of $\hat{p}$ can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

np ≥ 10
nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of $\hat{p}$ as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0

3 years ago