Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
The triangle of height 5 units and base 7 units will be as follows:
Answer:
Angle 50 and common side, in triangle MNT the sum of angles m and t is 130. In triangle PMN the sum of angles n, m is 130
Step-by-step explanation:
Answer:
Loss is Rs. 78
Step-by-step explanation:
Solution:
Given,
- Cost Price (CP)= Rs.1560
- Loss Percent (L%) = 5%
Here,
L%= L/CP ×100%
or,. 5 =L/1560×100
or,. 5×1560/100 =L
or,. L= Rs.78
Therefore, Loss is Rs.78
