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Lady bird [3.3K]
3 years ago
12

When 20.0 mL of an acetic acid (CH3COOH) solution is titrated with a 0.0610 M sodium hydroxide (NaOH) solution, the equivalence

point in the titration is 41.09 mL.
a) What was the concentration of acetic acid solution?

b) What are the [H3O+], [OH] and [CH3COO] at the equivalence point?

c) What is the pH at the equivalence point?

Note: The Ka for acetic acid (CH3COOH) is 1.74 × 10^-5.
Chemistry
1 answer:
Zolol [24]3 years ago
4 0

Answer:

Solution that is 0.100 M CH3COOH (acetic acid)

and 0.100 M NaCH3COO (sodium acetate)

Find pH of buffer solution:

CH3COOH(aq) + H2O ↔ CH3COO-

(aq) + H3O+(aq)

[CH3COOH] [CH3COO-

] [H3O+]

initial 0.100 0.100 ≈0

-x x x

equil 0.100 – x 0.100 + x xFind pH of buffer solution:

CH3COOH(aq) + H2O ↔ CH3COO-

(aq) + H3O+(aq)

Ka = [CH3COO-

][H3O+

]

[CH 3COOH] = (.100 + x)x

(.100 - x) = 1.8 x 10-5

x = 1.80 x 10-5 M

pH = 4.7

Explanation:

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Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = R=\frac{8.24 mL}{t}

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = R'=\frac{3.86 mL}{t}

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}

\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}

M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol

4 0
3 years ago
Write electron configurations for each of the following. the cations: Mg2+,Sn2+,K+,Al3+,Tl+,As3+
Eddi Din [679]

Answer:

  • Mg⁺² ⇒ 1s² 2s² 2p⁶
  • Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
  • K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶
  • Al³⁺ ⇒ 1s² 2s² 2p⁶
  • Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
  • As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Explanation:

The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.

Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus

Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.

In a similar fashion, the answers are:

Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶

Al³⁺ ⇒ 1s² 2s² 2p⁶

Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰

As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

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3 years ago
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Explanation:

First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.

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Explanation:

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