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GuDViN [60]
3 years ago
13

Saponification is a chemical reaction _____. A. due to the presence of a strong organic acid. B. that results in an alcohol and

a carboxylic acid. C. that explains why soap does not wash off easily in hard water. D. that always results directly in a soap.

Chemistry
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

that results in an alcohol and a carboxylic acid.

Explanation:

Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.

For Example, when a base such as sodium hydroxide [NaOH]  is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.

In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide  yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.

i.e  Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol

As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:

The reaction goes to completion in the image below:

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kompoz [17]
For the first one I think it’s A, and I think the second one is C. Those seem most logical.
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3 years ago
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You have 750 grams of water at 80° Celsius. Which of the following would lower the temperature of the water by 10° Celsius? (1 p
dem82 [27]

Answer:

adding 750 grams of water at 60° Celsius .

Explanation:

  • We can calculate the amount of heat lost from  750 grams of water at 80°C to be lowered by 10°C using the relation:

<em>Q = m.c.ΔT,</em>

Where, Q is the amount of heat lost by water (Q = ??? J).

m is the mass of water (m = 750.0 g).

c is the specific heat capacity of the water (c = 4.18 J/g.°C).

ΔT is the temperature difference (ΔT = final T - initial T = - 10.0°C, the temperature of water is lowered by 10.0°C).

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(- 10.0°C) = - 31350.0 J = -31.350 kJ.

Now, we can calculate the Q that is gained by the different added amounts of water:

  • <em>adding 750 grams of water at 50° Celsius :</em>

ΔT = 70.0°C - 50.0°C = 20.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(20.0°C) = 62700.0 J = 62.70 kJ.

  • <em>adding 325 grams of water at 60° Celsius :</em>

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (325.0 g)(4.18 J/g.°C)(10.0°C) = 13585.0 J = 13.585 kJ.

  • <em>adding 750 grams of water at 60° Celsius :</em>

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(10.0°C) = 31350.0 J = 31.350 kJ.

  • <em>adding 1000 grams of water at 55° Celsius:</em>

ΔT = 70.0°C - 55.0°C = 15.0°C,

∴ Q = m.c.ΔT = (1000.0 g)(4.18 J/g.°C)(15.0°C) = 62700.0 J = 62.70 kJ.

  • So, the right choice is:

<em>adding 750 grams of water at 60° Celsius</em>

8 0
4 years ago
Monochloroacetic acid (HC2H2ClO2) is a skin irritant that is used in "chemical peels" intended to remove the top layer of dead s
yaroslaw [1]

<u>Answer:</u> The pH of the solution is 1.703

<u>Explanation:</u>

We are given:

Concentration of monochloroacetic acid = 0.31 M

The chemical equation for the dissociation of monochloroacetic acid follows:

                  HC_2H_2ClO_2\rightleftharpoons H^++C_2H_2ClO_2^-

<u>Initial:</u>               0.31

<u>At eqllm:</u>        0.31-x             x            x

The expression of K_a for above equation follows:

K_a=\frac{[H^+][C_2H_2ClO_2^-}}{[HC_2H_2ClO_2]}

We are given:

K_a=1.35\times 10^{-3}

Putting values in above equation follows:

1.35\times 10^{-3}=\frac{x\times x}{(0.31-x)}\\\\x=-0.021,0.0198

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

pH=-\log (0.0198)\\\\pH=1.703

Hence, the pH of the solution is 1.703

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