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insens350 [35]
2 years ago
12

How did electrons gain energy in order to jump to higher energy levels?

Chemistry
1 answer:
Alla [95]2 years ago
3 0

Answer: An electron will jump to a higher energy level when excited by an external energy gain such as a large heat increase or the presence of an electrical field, or collision with another electron.

Explanation:

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A buffer consists of 0.120 M HNO2 and 0.150 M NaNO2 at 25°C. pka of HNO2 is 3.40. a. What is the pH of the buffer? b. What is th
Mashcka [7]

Explanation:

It is known that K_{a} of HNO_{2} = 4.5 \times 10^{-4}.

(a)  Relation between K_{a} and pK_{a} is as follows.

                       pK_{a} = -log (K_{a})

Putting the values into the above formula as follows.

                      pK_{a} = -log (K_{a})

                                    = -log(4.5 \times 10^{-4})

                                     = 3.347

Also, relation between pH and  pK_{a} is as follows.

              pH = pK_{a} + log\frac{[conjugate base]}{[acid]}

                     = 3.347+ log \frac{0.15}{0.12}

                    = 3.44

Therefore, pH of the buffer is 3.44.

(b)   No. of moles of HCl added = Molarity \times volume

                                            = 11.6 M \times 0.001 L

                                             = 0.0116 mol

In the given reaction, NO^{-}_{2} will react with H^{+} to form HNO_{2}

Hence, before the reaction:

No. of moles of NO^{-}_{2} = 0.15 M \times 1.0 L

                                           = 0.15 mol

And, no. of moles of HNO_{2} = 0.12 M \times 1.0 L

                                               = 0.12 mol

On the other hand, after the reaction :  

No. of moles of NO^{-}_{2} = moles present initially - moles added

                                          = (0.15 - 0.0116) mol

                                          = 0.1384 mol

Moles of HNO_{2} = moles present initially + moles added

                               = (0.12 + 0.0116) mol

                                = 0.1316 mol

As, K_{a} = 4.5 \times 10^{-4}

           pK_{a} = -log (K_{a})

                         = -log(4.5 \times 10^{-4})

                         = 3.347

Since, volume is both in numerator and denominator, we can use mol instead of concentration.

As, pH = pK_{a} + log \frac{[conjugate base]}{[acid]}

            = 3.347+ log {0.1384/0.1316}

            = 3.369

            = 3.37 (approx)

Thus, we can conclude that pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37.

6 0
3 years ago
A car travels 150 meters in 3.5 seconds what is its speed?
defon

Answer:

The solution is given below.

Explanation:

Speed   = Distance(m)/Time(sec.)

Distance traveled = 150 m

Time taken = 3.5 seconds

Speed of car = 150/3.5 = 42.86 m/s

So the car traveled at a speed of 42.86 m/s.

6 0
3 years ago
A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead(II)
melamori03 [73]
The answer is going to be 2.5
6 0
3 years ago
Which of the following statements does not describe a chemical property of oxygen:
g100num [7]
I have a feeling that #2 is the one.
5 0
3 years ago
How many moles of sulfate ions are in a sample of aluminum sulfate in which the number of formula units is 7.534 × 1023?
valentina_108 [34]

Answer:a unit of grammatical organization next below the sentence in rank and in traditional grammar said to consist of a subject and predicate

Explanation:

7 0
2 years ago
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