The correct answer is hydrogen<span>, and </span>oxygen<span>. </span>
Answer: Option (3) is the correct answer.
Explanation:
When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.
Atomic number of chlorine is 17. So, number of electrons present in
is 17 + 1 = 18 electrons.
Atomic number of cobalt is 27. So, number of electrons present in
is 27 - 4 = 23 electrons.
Atomic number of iron is 26. So, number of electrons present in
is 26 - 2 = 24 electrons.
Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.
Atomic number of scandium is 21. So, number of electrons present in
is 21 + 2 = 23 electrons.
Thus, we can conclude that out of the given species,
has the greatest number of electrons.
CₓHₐ + (x+a/4)O₂ = xCO₂ + a/2H₂O
n(CO₂)=4.69 mg/44.01 mg/mmol = 0.1066 mmol
n(H₂O)=1.10 mg/18.02 mg/mmol = 0.06104 mmol
C : H = 0.1066 : 0.06104*2 = 0.1066 : 0.12208 = 1 : 1.1453 = 7 : 8
C₇H₈ + 9O₂ = 7CO₂ + 4H₂O
C₇H₈