Its already balanced, no balancing required
Vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa then the absolute pressure in the chamber and express is 57kpa
Gauge pressure is the pressure relative to atmospheric pressure. Gauge pressure is positive for pressures above atmospheric pressure, and negative for pressures and absolute pressure is the sum of gauge pressure and atmospheric pressure
Here to find absolute pressure atmospheric pressure=92kpa and vacuum gage=35 kpa
Pabsolute pressure=Patmospehric pressure - Pvaccume
92-35=57kpa
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The 2 hormones are insulin & glucagon.
A hormone will only act on a part of the body it 'fits'. A hormone can be thought of as a key, and its target site ( i.e an organ) has specially shaped locks on the cell walls.
If the hormone fits, then it will work.
The hormone can set off a cascade of other singling pathways in the cell to cause an immediate effect ( for instance, insulin signaling leads to a rapid uptake of glucose in muscle cells)
The endocrine system is a tightly regulated system that keeps the hormones and their effects at just the right level. One way this is achieved is through ' feedback loops'. The release of hormones is regulated by other hormones, proteins or neuronal signals.
The released hormone then has its effect on other organs. This effect on the organ feeds back to the original signal to control any further hormone release.
btw- found all this info @ the Better Health channel, an australian government health website , so if your still confused by my answer, check out this website
www.betterhealth.vic.gov.au/health/conditionsandtreatments/hormonal-endocrine-system
Answer:
2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation
moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles
moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2
Propanol is limiting based on the mol ratio in balance equation of 2 : 9
To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.
moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used
moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left
mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over
Answer:
8)acids are electron pair acceptors and bases are electron pair donors
9)monoprotic
10)weak acids