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Snowcat [4.5K]
4 years ago
13

Describe the ph changes expected if an acid is used to neutralize a base with ph12

Chemistry
1 answer:
ad-work [718]4 years ago
4 0
It becomes neutral because acid neutralises the alkaline base
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Please only answer if you know the actual thing, don't search it up! Are these correct? :P
makkiz [27]

Hey buddy I am here to help!

1. C

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4 0
3 years ago
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What is the main type of weathering in deserts? weathering by organic acids chemical weathering physical weathering
Solnce55 [7]

Answer:

chemical

Explanation:

Chemical weathering, which is the decomposition of a rock by the alteration of its chemical composition.

5 0
3 years ago
August kekule described the various ring structures of the carbon compound benzene. What type of chemist would he be considered
Andreyy89
B.  He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.
3 0
3 years ago
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14. What is the total number of kilojoules of heat needed to change 150. G of
Nadusha1986 [10]

Answer:

\boxed {\boxed {\sf 50.1 \ kJ}}

Explanation:

When water changes from ice (solid) to water (liquid), it is melting or fusion. Therefore, we can use the following formula to find energy:

q=mH_f

where <em>q</em> is the energy, <em>m </em>is the mass, and <em>Hf</em> is the heat of fusion.

1. Define Values

The mass is 150 grams. The heat of fusion for water is 334 Joules per gram.

m= 150 \ g \\H_f=334 \ J/g

2. Calculate Energy

Substitute the values into the formula.

q=150 \ g * 334 \ J/g

Multiply. Note that the grams (g) will cancel each other out and leave Joules as our units.

q=150 *334 \ J

q=50100 \ J

3. Convert Units

We found the answer in joules, but the question asks for kilojoules, so we must convert.

There are 1000 Joules in 1 kilojoule. Therefore, we can divide the joules calculated by 1000.

50100 \ J *\frac{1 \ kJ}{1000 \ J}

\frac{50100 \ kJ}{1000 \ }

50.1 \ kJ

<u>50.1 kilojoules </u>are needed to change 150 grams of ice to water.

8 0
3 years ago
A+common+iv+solution+is+0.9%+saline+(nacl+solution).+what+is+the+osmolarity+of+0.9%+saline+mosmoles/l?+the+molecular+weight+of+n
Vedmedyk [2.9K]

An osmolarity of saline solution is 308 mosmol/L.

m(NaCl) = 9 g; the mass of sodium chloride

V(solution) = 1 L; the volume of the saline solution

n(NaCl) = 9 g ÷ 58.44 g/mol

n(NaCl) = 0.155 mol; the amount of sodium chloride

number of ions = 2

Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.

The osmolarity = n(NaCl) ÷ V(solution)  × 2

The osmolarity = 0.154 mol ÷ 1 L × 2

The osmolarity = 0.154 mol/L × 1000 mmol/m × 2

The osmolarity of the saline solution = 308 mosm/L.

More about osmolarity: brainly.com/question/13258879

#SPJ4

8 0
1 year ago
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