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Snowcat [4.5K]
3 years ago
13

Describe the ph changes expected if an acid is used to neutralize a base with ph12

Chemistry
1 answer:
ad-work [718]3 years ago
4 0
It becomes neutral because acid neutralises the alkaline base
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cricket20 [7]
No idea.. I think if you take angle (<) MNL then divide those...
7 0
2 years ago
A chemist prepares a solution of barium acetate by measuring out of barium acetate into a volumetric flask and filling the flask
leonid [27]

The given question is incomplete. The complete question is :

A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.

Answer:  The concentration of barium acetate solution is 0.375 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of Ba(CH_3COO)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{32g}{255g/mol}=0.125mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.125\times 1000}{350ml}

Molarity=0.357M

Therefore, the concentration of solution is 0.375 mol/L

8 0
3 years ago
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
love history [14]

Answer:

FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

Explanation:

Empirical formula of ionic compound formed by two ions A^{x+} and B^{y-} is A_{y}B_{x} (for x\neq y) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation (Fe^{3+} and Fe^{2+}) can form two ionic compounds by combining with two given anions (SO_{4}^{2-} and CH_{3}CO^{2-}).

So the four ionic compounds are: FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

4 0
3 years ago
There are two common oxides of copper; one is 80% copper and the other is 89% copper by weight. Calculate the formula and name e
irakobra [83]

80% copper (Cu)

Cu: 80 :  63.546 = 1.259

O: 20 : 16 = 1.25

Cu:O = 1 : 1

the formula: CuO

89% copper (Cu)

Cu: 89 :  63.546 = 1.4

O: 11 : 16 = 0.6875

Cu:O = 2:1

the formula: Cu₂O

8 0
2 years ago
Is it fair that some scientists have received more credit than others for their work on the development of the periodic table? W
Gre4nikov [31]
Yes because some work harder than others to get their credit for developing the periodic table
6 0
3 years ago
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