Answer:
d
. Sc2O5
Explanation:
Hello,
In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:
For that reason, the answer is d
. Sc2O5
Best regards.
There are two hydrogen and two oxygen molecules because the number next to the atomic number is how many there are.
Answer:
Rate = k [OCl] [I]
Explanation:
OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.
In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.
In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.
The rate law is given as;
Rate = k [OCl] [I]
Explanation:
Number of moles(n)=Number of atoms(N)/Avogadro's constant.
Avogadro's constant=6.02×10²³
so we have
n=9.05×10²³/6.02×10²³
n=1.0503moles.
n=mass/molar mass
1.0503=mass/28
mass=1.0503×28
mass=29.4084g
Answer:
I'm pretty sure this is a question about your opinion so there is no wrong answer! Just think about the question and if you were in those shoes. There is no right or wrong answer! :)
Explanation:
