Answer:
(20 miles/inch) * (3.5 inches) = 70 miles
Step-by-step explanation:
Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q
Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters.
p + d + p = 43 (1)
p = d (2)
p +10d +25q = 451 (3)
Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.
Put the results of 2 into 1.
2p + q = 43 (4)
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q = 451 (5)
Solve the new equations
2p + q = 43 (4)
11p + 25q = 451 (5)
Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075 (6) Subtract (5) from (6)
<u>11p + 25q = 451
</u>39p = 624 Divide by 39
p = 624 / 39
p = 16
Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11
Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275 = ?
451 = ?
Nice problem. Thanks for posting.
Answer:
609
Step-by-step explanation:
All you must do is multiply 1450 by 0.42. That would give you the total.
Answer:
m > 2
Step-by-step explanation:
Since it is an open dot, it is not greater than or equal to, but rather just greater than.
Then, since the arrow goes to the right, the equation is greater than.
Using the law of cosine for Triangle KJL, we can write:
![j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\ \\ cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}](https://tex.z-dn.net/?f=%20j%5E%7B2%7D%20%3D%20k%5E%7B2%7D%20%2B%20l%5E%7B2%7D-2%28k%29%28l%29cos%28J%29%20%20%5C%5C%20%20%5C%5C%20%0A2%28k%29%28l%29cos%28J%29%3Dk%5E%7B2%7D%20%2B%20l%5E%7B2%7D-%20j%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20%0Acos%28J%29%3D%20%5Cfrac%7Bk%5E%7B2%7D%20%2B%20l%5E%7B2%7D-%20j%5E%7B2%7D%7D%7B2%28k%29%28l%29%7D%20%20)
Using the values of k,j and l, we can write:
![cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ cos(J)= 0.664 \\ \\ J= cos^{-1}(0.664) \\ \\ J=48.39](https://tex.z-dn.net/?f=cos%28J%29%3D%20%5Cfrac%7B%204%5E%7B2%7D%20%2B%20%282.89%29%5E%7B2%7D%20-%203%5E%7B2%7D%20%7D%7B2%284%29%282.89%29%7D%20%20%5C%5C%20%20%5C%5C%20%0Acos%28J%29%3D%200.664%20%5C%5C%20%20%5C%5C%20%0AJ%3D%20cos%5E%7B-1%7D%280.664%29%20%5C%5C%20%20%5C%5C%20%0AJ%3D48.39%20)
Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer