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Dima020 [189]
3 years ago
9

25. Jared works at a pet store. He is showing a customer a small aquarium that measures 3 feet by 1.5 feet and is 2 feet deep. A

large aquarium has double the size of the small aquarium in each dimension, 6 feet by 3 feet by 4 feet. Jared tells the customer that the large tank holds twice as much water as the small tank. Is jared correct?
A)No, the large tank holds the same amount of water
B) No, the large tank holds 4 times as much water
C) Yes, the large tank holds exactly 2 times as much water as the small tank
D) No, the large tank holds 8 times as much water as the small tank
Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Hi!

For this question, you want to find the volume of each aquarium. To find volume, just multiply all the dimensions dogether.

For the small aquarium: 3 * 1.5 * 2 = 9 feet cubed

For the large aquarium: 6 * 3 * 4 = 72 feet cubed

Therefore, no, he is not correct, as the large aquarium holds 8 times as much water as the small one. Option D is correct.

If you would like a faster way to do this, if you look at the two dimensions, you'll see each dimension for the large aquarium is two times the respective dimensions of the small one. Since there are three dimensions, and each is two times larger, you can just do 2 * 2 * 2 to get 8 times, as the dimensions are all multiplied with one another.

Hope this helped!

madam [21]3 years ago
4 0

Answer:

D) No, the large tank holds 8 times as much water as the small tank.

Step-by-step explanation:

The dimensions of small aquarium is 3 feet by 1.5 feet by 2 feet.

Its volume is :

3\times1.5\times2=9 cubic feet.

The dimensions of the large aquarium is 6 feet by 3 feet by 4 feet.

Its volume is :

6\times3\times4=72 cubic feet.

Larger tank holds \frac{72}{9} = 8 times the volume of smaller tank.

Jared tells the customer that the large tank holds twice as much water as the small tank.

No, Jared is not correct because the large tank holds 8 times as much water as the small tank.

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Complete the work to find the dimensions of the rectangle. x(x – 3) = 10 x2 – 3x = 10 x2 – 3x – 10 = 10 – 10 (x + 2)(x – 5) = 0
Norma-Jean [14]

Answer:

Length =5

Width = 2

Step-by-step explanation:

Given

Length =x

Width = x -3

Area = 10

x(x-3) =10

See comment for missing part of the question

Required

Complete the expression to determine the dimension of a rectangle

We have:

x(x-3) =10

Open bracket

x^2 -3x = 10

Equate to 0

x^2 -3x - 10 =0

Expand

x^2 + 2x - 5x - 10 = 0

Factorize

x(x + 2) - 5(x + 2) = 0

Factor out x + 2

(x  - 5)(x + 2) = 0

Solve for x

x - 5 = 0 or x + 2 = 0

x = 5 or x = -2

The value of x cannot be negative

So:

x  = 5

Recall that:

Length = x

Width = x - 3

So:

Length =5

Width = 2 ---- i.e. 5 - 3

6 0
3 years ago
Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri
borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= 8\dfrac{3}{4}\ miles

The length of Maddie’s bike ride=3\dfrac{1}{2}\ miles

In improper fraction : Length of Chase’s bike ride=\dfrac{4(8)+3}{4}\ miles

=\dfrac{35}{4}\ miles

Similarly , Length of Maddie’s bike ride= \dfrac{7}{2}\ miles

The number of times the length of Chase’s bike ride was Maddie’s bike ride= \dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}

=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0
3 years ago
Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker
LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

<u><em>Let X = Math scores on the SAT exam</em></u>

So, X ~ Normal(\mu=514,\sigma^{2} =118^{2})

The z score probability distribution for normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma} ~  N(0,1)

where, \mu = population mean score = 514

           \sigma = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

       P(455 < X < 573) = P(X < 573) - P(X \leq 455)

       P(X < 573) = P( \frac{X-\mu}{\sigma} < \frac{573-514}{118} ) = P(Z < 0.50) = 0.69146

       P(X \leq 2.9) = P( \frac{X-\mu}{\sigma} \leq \frac{455-514}{118} ) = P(Z \leq -0.50) = 1 - P(Z < 0.50)

                                                         = 1 - 0.69146 = 0.30854

<em>The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.</em>

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = <u>0.38292</u>

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0
3 years ago
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Tcecarenko [31]

Answer:

seashells / week

Step-by-step explanation:

Your answer is correct, seashells / week.

Units are:

s(t) = seashells / hour

W(h) = hours / week

so

s(W(h) represents seashells / hour * hours / week,

simplifying, the units are

seashells / week

5 0
3 years ago
Which expression is equivalent to (sin x + 1)(sin x − 1)? A. cos2x B. -cos2x C. cos2x + 1 D. cos2x − 1 E. -cos2x + 1
Semenov [28]

ANSWER

B.

- \cos^{2} x

EXPLANATION

The given expression is

(sin x + 1)(sin x − 1)

Note that:

(x + 1)(x - 1) =  {x}^{2}  - 1

This implies that,

( \sin \: x + 1)( \sin \: x - 1)  =   \sin^{2} x - 1

We can factor -1 on the right hand side to get,

( \sin \: x + 1)( \sin \: x - 1)  =    - (1 - \sin^{2} x )

Note that from the Pythagorean Identity

1 - \sin^{2} x = \cos^{2} x

We apply this identity to obtain:

( \sin \: x + 1)( \sin \: x - 1)  = - \cos^{2} x

The correct choice is B

4 0
3 years ago
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