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Dima020 [189]
3 years ago
9

25. Jared works at a pet store. He is showing a customer a small aquarium that measures 3 feet by 1.5 feet and is 2 feet deep. A

large aquarium has double the size of the small aquarium in each dimension, 6 feet by 3 feet by 4 feet. Jared tells the customer that the large tank holds twice as much water as the small tank. Is jared correct?
A)No, the large tank holds the same amount of water
B) No, the large tank holds 4 times as much water
C) Yes, the large tank holds exactly 2 times as much water as the small tank
D) No, the large tank holds 8 times as much water as the small tank
Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Hi!

For this question, you want to find the volume of each aquarium. To find volume, just multiply all the dimensions dogether.

For the small aquarium: 3 * 1.5 * 2 = 9 feet cubed

For the large aquarium: 6 * 3 * 4 = 72 feet cubed

Therefore, no, he is not correct, as the large aquarium holds 8 times as much water as the small one. Option D is correct.

If you would like a faster way to do this, if you look at the two dimensions, you'll see each dimension for the large aquarium is two times the respective dimensions of the small one. Since there are three dimensions, and each is two times larger, you can just do 2 * 2 * 2 to get 8 times, as the dimensions are all multiplied with one another.

Hope this helped!

madam [21]3 years ago
4 0

Answer:

D) No, the large tank holds 8 times as much water as the small tank.

Step-by-step explanation:

The dimensions of small aquarium is 3 feet by 1.5 feet by 2 feet.

Its volume is :

3\times1.5\times2=9 cubic feet.

The dimensions of the large aquarium is 6 feet by 3 feet by 4 feet.

Its volume is :

6\times3\times4=72 cubic feet.

Larger tank holds \frac{72}{9} = 8 times the volume of smaller tank.

Jared tells the customer that the large tank holds twice as much water as the small tank.

No, Jared is not correct because the large tank holds 8 times as much water as the small tank.

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fiasKO [112]

The correct rectangular equivalence of 3sqrt(2)·cis(7pi/4 ) is:

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<h3>Where did David go wrong?</h3>

David mistakenly interchanged the Sin function and the Cos function when he was calculating the problem.

Hence the correct rectangular equivalence is:

3sqrt(2)·cos( 7pi/4 ) + i·sqrt(2)·sin( 7pi/4 )  =  3 - 3i.

<h3>What is rectangular equivalence?</h3>

An equation is rectangular in form when it is comprised of Variables like X and Y and can be represented on a Cartesian Plane.

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