Question

ZA and ZB are complementary angles. If m_A = (6x – 4)º and m

Answer 1

$\\ \sf\longmapsto 6x-4+x+17=90$

$\\ \sf\longmapsto 7x+13=90$

$\\ \sf\longmapsto 7x=90-13=77$

$\\ \sf\longmapsto x=11$

Answer 2

Answer:

$62 \degree$

Step-by-step explanation:

Complementary Angles are added up to 90°

Therefore,

$6x - 4 + x + 17 = 90 \\ 7x + 13 = 90 \\ 7x = 90 - 13 \\ 7x = 77 \\ \frac{7x}{7} = \frac{77}{7} \\ x = 11$

So,

$ZA = 6x - 4 \\ = 6 \times 11 - 4 \\ = 66 - 4 \\ = 62 \degree$

Hope this helps you.

Let me know if you have any other questions :-)