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morpeh [17]
3 years ago
6

I'LL GIVE BRAINLIEST A or D

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Think of what the egyptians built wayyyy back then (Hint: Pyramids)

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Assets are 19.4% total amount
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triangle ABC was rotated 90 degrees clockwise. Then it underwent a dialtion centered at the origin with a scale factor of 4 what
scoray [572]

Answer: The angles of ΔA'B'C are congruent to the corresponding parts of the original triangle.

Step-by-step explanation:

Given : Triangle ABC was rotated 90 degrees clockwise. Then it underwent a dilation centered at the origin with a scale factor of 4.

A rotation is a rigid transformation that creates congruent images but dilation is not a rigid transformation, it creates similar images but not congruent.

Also, the corresponding angles of similar triangles are congruent.

Therefore, The angles of ΔA'B'C are congruent to the corresponding parts of the original triangle.

4 0
3 years ago
Simplifying exponents (picture provided)
Hitman42 [59]

Answer:

<em>3^2 ; Option B</em>

Step-by-step explanation:

We are given the equation 3^ -6 * ( 3^4 / 3^0 )^2, which can be solved through the application of exponential rules;

3^{ - 6 } * ( 3^{ 4 } / 3^{ 0 } )^{2} - take 3^{ 0 } as 1,\\\\3^{ - 6 } * ( 3^{ 4 } / 1 )^{2} - take 3^{4} to power of 2, ( * of exponents ),\\\\3^{ - 6 } * ( 3^{ 8 } ) - combine powers, adding exponents,\\\\3^{ - 6 + 8 } - add like terms,\\\\3^{2} \\\\Solution; 3^{2}

<em>3^2 ; Option B</em>

7 0
3 years ago
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X-3y=8 what is y in this question
gogolik [260]

y=5, x=7 because if 3x5=15 then 15-7=8 dont report me if i do get this wrong

7 0
4 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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