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3 years ago

HELP ASAP WILL MARK BRAINLIEST

Mathematics

2 answers:

STatiana [176]3 years ago

3 0

Answer:

4 hours

Step-by-step explanation:

Formula for volume of a cylinder is πr² · h

1. Find the volume of the pool

π(3.5²) · 1.9 = 73.1 m³

2. Divide by the amount of water pumped out per hour (17 m³)

73.1 ÷ 17 = 4.3

It would take 5 hours to completely empty the pool but 4.3 rounded to the nearest whole hour is 4 hours.

anygoal [31]3 years ago

3 0

Answer:

The hours does it take to empty the pool is 4.299

Step-by-step explanation:

In order to calculate how many hours does it take to empty the pool, we would have to make the following calculation:

hours does it take to empty the pool=Volume of cylinder/rate water is pumped out of the pool

rate water is pumped out of the pool=17m∧3

Volume of cylinder=pi*r∧2*l

According to the given data:

r=3.5

l=1.9

Therefore, Volume of cylinder=3.14*3.5∧2*1.9

Volume of cylinder=73.0835 m∧3

hours does it take to empty the pool=73.0835/17

hours does it take to empty the pool=4.299

The hours does it take to empty the pool is 4.299

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A rectangle pool is 7 ft wide, it is 3 times as long as it is wide what’s the dimensions of the pool?

svetoff [14.1K]

The length is 3 times longer than the width (7)

3 x 7 = 21

the length is 21.

To find perimeter, add all sides together:

21 + 21 + 7 + 7 = 42 + 14 = 56

56 ft is your answer

hope this helps

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3 years ago

Read 2 more answers

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4 years ago

ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12.

Naily [24]

Answer:

Explained below.

Step-by-step explanation:

(11)

Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

$[(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z$

Thus, the final expression is (-11x + y - 12z).

(12)

From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).

$[(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5$