Answer:
![9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=9c%5E3%20-%2012c%5E2%20-%2018c%20-%2024%3D%20%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
Step-by-step explanation:
Given

Required
Factor
Group into 2
![[9c^3 - 12c^2] - [18c + 24]](https://tex.z-dn.net/?f=%5B9c%5E3%20-%2012c%5E2%5D%20-%20%5B18c%20%2B%2024%5D)
Factorize each group
![3c^2[3c - 4] - 6[3c - 4]](https://tex.z-dn.net/?f=3c%5E2%5B3c%20-%204%5D%20-%206%5B3c%20-%204%5D)
Factor out 3c - 4
![[3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
Hence:
![9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=9c%5E3%20-%2012c%5E2%20-%2018c%20-%2024%3D%20%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
Answer:
it would be subtraction
Step-by-step explanation:
Because if you are trying to get you would do 2-2 to get 0 and have x by itself
The answer to your question is
No
Answer:
12
Step-by-step explanation:
Let the number = x
7x + 1 = 5x + 25 Subtract 5x from both sides.
7x - 5x + 1 = 5x - 5x + 25 Combine
2x + 1 = 25 Subtract 1 from both sides.
2x + 1 - 1 = 25-1 Combine
2x = 24 Divide by 2
2x/2 = 24/2
x = 12