Volume of the first dwarf planet (r₁ = 832 mi):

Volume of the second dwarf planet (r₂ = 829 mi):

So difference between the volumes is:

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):
Answer:
angles 2 and 10 are corresponding Angles while angles 6 and 11 are alternate Angles
The perimiter is 4 times 1 side
currently, it is 9 times 4 or 36
increased by 3
I think y mean times 3
so 9*3=27
new perimiter is 27*4=108
how much larger is it?
108-36=72
it is 72cm larger
it is the first answer
(it isn't cm² because that is for area and we are calculating perimiter)
Answer:
The median is 2
Step-by-step explanation:
Here, we want to get the median for the number of pencils
Firstly, we have to write out the numbers that form the box plot ; we have this as;
1,1,1,2,2,2,2,3,3,5
the median is sum of the 5th and 6th term divided by 2
The 5th term is 2
The 6th term is 2
So the median is;
(2 + 2)/2
= 4/2 = 2
Answer:
1 + root 5, 1 - root 5
Step-by-step explanation:
I assume you mean 3x^2-6x-12=0.
First, note that you can divide both sides by 3. You get:
x^2-2x-4=0
Use the quadratic equation.

Therefore, x=1 + root 5, 1 - root 5