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luda_lava [24]
2 years ago
15

1. A two-dimensional form that occupies an area is called a(n) . 2. A(n) is a three-dimensional form that occupies a volume of s

pace. 3. A shape we detach and focus on is known as the . 4. The is surrounding visual information. 5. A shape that stands out to the viewer can be called a(n) . 6. A shape that is part of the background can be called a(n) . 7. A(n) approximates regular, named shapes, such as a square, triangle, or circle. 8. A(n) is irregular and evokes the living forms of nature.
Mathematics
2 answers:
anyanavicka [17]2 years ago
7 0

Answer:

Step-by-step explanation:

1. Plane shape

2. mass

3.  figure

4. ground

5. Positive shape

6.  negative shape

7.) geometrical shape

8) organic shape

MrRissso [65]2 years ago
4 0

Answer:

1) Plane shape

2) Solid shape

3)      

4) Perimeter

5) Aerial view

6)  Shadow

7) Mensuration

8) Water

Step-by-step explanation:

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Classify the statement as either true or false.<br> lim<br> 6 = 6
asambeis [7]

Answer:

false

Step-by-step explanation:

if is 6= you need to time by it self like: 6×6=is ur answer

4 0
3 years ago
What is the area and perimeter. please answer asap ​
Airida [17]

Answer:

Perimeter: 24

Area: 1105.92

Step-by-step explanation:

Perimeter:

Add up all of the numbers

Area:

Multiply all of the numbers

(I'll redo it if this isn'twhat you meant by)

7 0
3 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
3 years ago
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Nikolay [14]

Answer:

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Step-by-step explanation:

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3 0
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Answer:

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