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worty [1.4K]
3 years ago
7

Asap please help math evaluate algebra

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

a. is equal to -21

b. is equal to -1

c. is equal to 31

Step-by-step explanation:

a. 2(-2)²-5

-4²-5

-16-5

= -21

b.2(1)²-5

2²-5

4-5

= -1

c.2(3)²-5

6²-5

36-5

= 31

This is the correct answers,please mark brainliest.

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Write a trinomial in one variable of degree 5 in standard form.
Mamont248 [21]

A polynomial of one-variable is given by following expression :-

Ax^n + Bx^{n-1} +Cx^{n-2}+Dx^{n-3}+Ex^{n-4}+.....

where A, B, C, D, E are the coefficients of terms in the polynomial and x is variable of the equation.

A is the leading coefficient and it can not be zero i.e. A≠0.

n is the degree of the polynomial.

It says to write a trinomial in one variable of degree 5.

Trinomial means only three terms with non-zero coefficients, and degree 5 means n = 5.

There could be many answers, but an example of "trinomial of degree 5" would be :-

Ax^5 + Bx^4 + Cx^3

3x^5 + 5x^4 + 2x^3

8 0
3 years ago
What is the distance between (Negative 5, 4) and (Negative 1, 4)?
Illusion [34]

Answer:

The answer would be 4 units

Step-by-step explanation:

Hope this helps!!!

4 0
3 years ago
8. The high school graduating class of 2000 was 260 students. Five years later, the graduating class was 320 students. By 2010,
olga nikolaevna [1]

Answer:

the question is confusing but the answer is 2010

Step-by-step explanation:

because in the year 2000 it was

260

then increased by

60

over 5 years making the next class

320

then in 2010 it was

400

and 320 + what is 400?

80

so the answer is:

2010

4 0
3 years ago
Can someone answer these questions ? thank you
Naya [18.7K]

Answer:

Step-by-step explanation:

12a)To rationalize the denominator, multiply the denominator and numerator by √5.

\frac{15}{\sqrt{5}}=\frac{15*\sqrt{5}}{\sqrt{5}*\sqrt{5}}\\\\=\frac{15\sqrt{5}}{5}\\\\=3\sqrt{5}

b) (a+b)² = a² + 2ab + b²

(1 +√3)² = 1² + 2*1*√3 + (√3)²

= 1 + 2√3 + 3

= 4 + 2√3

a = 4 ; b =2

13) (a + b)(a - b) = a² - b²

\frac{(6-\sqrt{5})(6+\sqrt{5})}{\sqrt{31}}=\frac{6^{2}-(\sqrt{5})^{2}}{\sqrt{31}}\\\\ =\frac{36-5}{\sqrt{31}}\\\\=\frac{31}{\sqrt{31}}\\\\=\frac{31*\sqrt{31}}{\sqrt{31}*\sqrt{31}}\\\\=\frac{31\sqrt{31}}{31}\\\\=\sqrt{31}

5 0
4 years ago
I just don't know where to start. I'm doing Algebra 2 stuff with sohcahtoa.
mezya [45]

Hello!

As you can see, 22 is the opposite angle. We are looking for the adjacent angle. Let's just call it x. Using SOH CAH TOA, we see that the tangent is the opposite divided by the adjacent side. Let's use that.

tan54≈1.38

This gives us the equation below.

1.38=22/x

Let's solve this equation for x.

1.38x=22

x=22/1.38

x=15.94

Therefore, the length of the shadow is about 15.94 meters.

I hope this helps!

7 0
3 years ago
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