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romanna [79]
3 years ago
5

What is the answer to negative twent c equals one hundred eighty

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

-0.25 or -¼

Step-by-step explanation:

-20c = 180

-20c/-20 = 180/-20

c = -0.25 or -¼

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F(x)=-(x+7)^2+4 which of the following
solmaris [256]

Answer:

(x+7)^2+4

Step-by-step explanation:

(x+7)^2 + 4

x^2+14x+49+4

x^2+24x+53

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3grade math help!!!
alekssr [168]
14+2(14)=42. this is the answer
7 0
3 years ago
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Help on 20, would be appreciated if there was a explanation as well
ra1l [238]
For a two column proof, we want to start with the given information. From there, we will use various definitions, postulates, and theorems to fill in the rest.

Our two sets of given information are that Plane <em>M </em>bisects Line <em>AB </em>and that Line <em>PA</em> is congruent to Line <em>PB</em>.

We know from the definition of a bisector that it splits a line in two equal parts. Therefore, Line <em>AO</em> must be congruent to Line <em>BO</em>.

Now, we have two sides of a triangle that we have proved to be congruent to each other. From the image given in the original problem, we see that both triangles share Line <em>OP. </em>Line <em>OP</em> is congruent to Line <em>OP</em> through the reflexive property.

We now have proven that all three sides of the one triangle are congruent to the corresponding sides on the other triangle. Therefore, the triangles are congruent through the SSS theorem. 

6 0
2 years ago
Indicate in standard form the equation of the line passing through the given points, writing the answer in the equation
Kryger [21]

Answer:

y + x - 6 = 0

Step-by-step explanation:

Given

M(0,6) \ and \ N(6,0)

Required

Find the equation of the line

First, the slope of the line has to be calculated using the following formula;

m = \frac{y_2 - y_1}{x_2 - x_1}

where\  (x_1,y_1) = (0,6) \ and \ (x_2,y_2) = (6,0)

So, the equation becomes

m = \frac{0 - 6}{6 - 0}

m = \frac{-6}{6}

m = -1

The equation of the line can then be calculated using

m = \frac{y - y_1}{x - x_1} \ or \ m = \frac{y - y_2}{x - x_2}

Using \ m = \frac{y - y_1}{x - x_1}

-1 = \frac{y - 6}{x -0}

-1 = \frac{y - 6}{x}

Multiply both sides by x

-1 * x = \frac{y - 6}{x} * x

-x = y - 6

Add x to both sides

x -x = y - 6 + x

0 = y - 6 + x

Reorder

y + x- 6 = 0

Using \ m = \frac{y - y_2}{x - x_2}

-1 = \frac{y - 0}{x - 6}

-1 = \frac{y}{x - 6}

Multiply both sides by x - 6

-1 * (x-6) = \frac{y}{x - 6} * (x-6)

-1 * (x-6) = y

-x+6 = y

Add x - 6 to both sided

x - 6 -x+6 = y +x - 6

0 = y + x - 6

y + x - 6 = 0

Hence, the equation of the line is y + x - 6 = 0

3 0
3 years ago
The vertices of the triangle shown are (-2, 2), (4, -1), and (-2, -3).
Rainbow [258]

Answer: 15

Step-by-step explanation:

8 0
3 years ago
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