Something's not quite right here. What do you mean by "N?"
I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)
Find the equation of a line through (0,2) <span>which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.
Using the point-slope form of the equation of a straight line:
y = (-1/3)x + 2 (answer)</span>
Answer:
B)5/3
Step-by-step explanation:
"3x + 5y = 15."
Rewrite in slope-intercept form.
The slope-intercept form is
y=mx+b
where m is the slope and b is the y-intercept.
y=mx+b
Subtract 3x from both sides of the equation.
5y=15−3x
Divide each term by "5" and simplify.
5y/5=15/5−3x/5
"5" and "5" cancel each other out
Divide 15 by 5
y=3-3x/5
Reorder 3 and −3x/5
y=-3x/5+3
Rewrite in slope-intercept form.
y=−3/5x+3
Slope:-3/5
The equation of a perpendicular line to y=−3x/5+3 must have a slope that is the negative reciprocal of the original slope.
<em>m</em>perpendicular=−1/(−3/5)
Simplify the result.
mperpendicular=5/3
hope this helps!
Divide 45 by 60 which gives you 0.75. To check your answer, multiply 0.75 by 60 then add that answer to -45. So, the answer is 0.75
5/4=15/12
2/3=8/12
15/12+8/12=23/12
