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Y_Kistochka [10]

2 years ago

14

How are exponential modelsare helpful in estimating future values of a function?

1 answer:

alexandr1967 [171]2 years ago

3 0

I think it’s 17.4 idk but hope it’s helpful

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Which set of measurements can represent the lengths of a triangle's sides? Classify each set of lengths as a Triangle or Not a t

Alexxx [7]

Answer:

1. Not a triangle
2. Not a triangle
3. Triangle
4. Triangle

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2 years ago

Simplify The Expression. 12/c^-8d^2

Katarina [22]

If you're going to write negative exponents, please enclose them inside parentheses:

12 / c^(-8)
12 8d^2
<span>12/c^-8d^2 becomes --------- - ---------
c^8 1

Here the LCD is c^8, so the above expression becomes:

12 c^8*d^2 12-(c^8)(d^2)
------- - ------------- = ---------------------
c^8 c^8 c^8</span>

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3 years ago

Please someone help

Karolina [17]

Answer:

cos is used if there is adjacent and hypotenuse

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3 years ago

Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc

Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

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3 years ago

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At a small university, there are 1800 female students and 2000 male students. Which of the following expresses the ratio of fema

jonny [76]

The answer to this is.9/10

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3 years ago

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