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DochEvi [55]
1 year ago
9

A map has a scale of 1 inch = 3 miles. Which of the following scales is equivalent?

Mathematics
2 answers:
defon1 year ago
7 0

Answer:

Step-by-step explanation:

77 inches

Step-by-step explanation:

Given

1 inch = 3 miles in map

We are also given the actual distance between City A and City B = 231 miles.

In order to get the distance in inches = Distance between City A and City B in miles/ 3

We are dividing the distance by 3 to get the distance in inches.

So,

Distance on map = 231/3

= 77 inches

tankabanditka [31]1 year ago
3 0
12 inch=36 miles because if you multiply 11 x 3 you get 36 miles.
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64=[(96 divided by 8) times 5]-42
bogdanovich [222]

Answer:

that statement is not true

Step-by-step explanation:

64=[(96÷8)5}-42

64={(12)5} - 42

64= (60)-42

64=18

but that with subtraction. if you multiply 60 by negative 42 you get -2520 which is still not true

7 0
3 years ago
Using the distributive property rewrite 2x + 16 as a product of two factors
tresset_1 [31]
2(x + 8)
Factor out the 2
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2 years ago
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Arturiano [62]

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Step-by-step explanation:

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2 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
2 years ago
Need help asap please no scammers!!!!!!!!!!!!!!!
galina1969 [7]

Answer:

111

Step-by-step explanation:

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