Algebra has variable. Finding the slope and y-intercept.
<span>Algebra tiene variable. Encontrar la pendiente y la intersección con el eje y</span>
ANSWER
EXPLANATION
If the graph of y=cosx is transformed to y=a cos (x−c)+d by a vertical compression by a factor of 1/3 and a translation 2 units down,
then
a=1/3
and d=-2.
The 'c' is a phase shift since it is not given, it means it is zero.
Therefore the new equation is:
y=1/3cos(x-0)−2
This simplifies to:
y=1/3cosx−2
The correct option is C.
By PEMDAS (or any alternative), <em>the first step should be to divide</em>, as D comes before A. So, 16 ÷ 4.
The lines that are the directrices of the ellipse is B. x = −3.25 and x = 9.25.
<h3>How to calculate the ellipse? </h3>
From the information given, the equation of parabola will be:
= (x - 3)²/5² + (y - 2)²/3² = 1
Hence, h = 3, k = 2, a = 5, b = 3
e = ✓1 - ✓3²/5²
E = 4/5 = 0.8
The directix will be:
x = 3 + 5/0.8
x = 9.25
x = 3 - 5/0.8
x = -3.25
Therefore, lines that are the directrices of the ellipse is x = −3.25 and x = 9.25.
Learn more about ellipse on:
brainly.com/question/16904744
Use the point slope equation: y - y1 = m(x - x1)
(-1, -3); m = 4
Plug these numbers in.
y - (-3) = 4(x - -1)
y + 3 = 4x + 4
y = 4x + 1
