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elena55 [62]
2 years ago
8

What is the standard form equation of an ellipse that has vertices (−2,−18) and (−2,8) and foci (−2,−14) and (−2,4)?

Mathematics
1 answer:
sveta [45]2 years ago
3 0

Answer:

Hello,

Step-by-step explanation:

All is in the picture.

B=(-2,8), O=(-2,-5)

b=BO=8+5=13

F_1=(-2,4)   O=(-2,5)  Focus distance=4+5=9
Horizontal half axis=√(b²-f²)=√88

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Let f(x)= [x/3] (where f(x) is the ceiling function). We learned that the floor and the ceiling functions are NOT invertible, bu
meriva

(a) We have ⌊<em>x</em>⌋ = 5 if 5 ≤ <em>x</em> < 6, and similarly ⌊<em>x</em>/3⌋ = 5 if

5 ≤ <em>x</em>/3 < 6   ==>   15 ≤ <em>x</em> < 18

(b) ⌊<em>x</em>⌋ = -2 if -2 ≤ <em>x</em> < -1, so ⌊<em>x</em>/3⌋ = -2 if

-2 ≤ <em>x</em>/3 < -1   ==>   -6 ≤ <em>x</em> < -3

In general, ⌊<em>x</em>⌋ = <em>n</em> if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is any integer.

I do not understand what is being asked in (c) and (d), so you'll have to clarify...

8 0
3 years ago
Clifford is making a really big white cake for his sisters birthday. The recipe calls for 1.5 times as much flour as sugar. It a
pantera1 [17]

<u>Answer:</u>

The amount of butter, sugar and flour does Clifford need is 2.5 cups flour, 3.75 cups sugar and 1.25 butter

<u>Explanation</u>:

Consider the number of cup of flour used to be x

According to question,

Recipe calls for 1.5 times as much flour as sugar

Sugar =1.5 \times Flour

Sugar = 1.5x

Butter = ½ x = 0.5x

According to question,  

Flour + Sugar + Butter = 7.5

x + 1.5x + 0.5x = 7.5

3x = 7.5

x = 2.5

Sugar = 1.5x = 1.5(2.5) = 3.75

Butter = 0.5(2.5) = 1.25

Clifford need is 2.5 cups flour, 3.75 cups sugar and 1.25 cups butter

3 0
3 years ago
Some1 help please :) dont answer if u are not 100% sure thank you
Natalija [7]

Answer:

Step-by-step explanation:

It's never negative.

5 0
3 years ago
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Consider the differential equation: y′′−8y′=7x+1. Find the general solution to the corresponding homogeneous equation. In your a
Margaret [11]

Answer:

yp = -x/8

Step-by-step explanation:

Given the differential equation: y′′−8y′=7x+1,

The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)

First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;

y′′−8y′=0

The auxiliary equation will give us;

m²-8m = 0

m(m-8) = 0

m = 0 and m-8 = 0

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Since the value of the roots are real and different, the complementary solution (yc) will give us

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yc = Ae^0+Be^8x

yc = A+Be^8x

To get yp we will differentiate yc twice and substitute the answers into the original DE

yp = Ax+B (using the method of undetermined coefficients

y'p = A

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Substituting the differentials into the general DE to get the constants we have;

0-8A = 7x+1

Comparing coefficients

-8A = 1

A = -1/8

B = 0

yp = -1/8x+0

yp = -x/8 (particular integral)

y = yc+yp

y = A+Be^8x-x/8

3 0
3 years ago
Can someone help lol
djverab [1.8K]

Answer:

p=30 q=150

Step-by-step explanation:

7 0
3 years ago
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