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RSB [31]
3 years ago
13

Helppppp me find a equation for this lol

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
6 0

Answer: One POSSIBLE answer is (0,9)

Step-by-step explanation: This may look hard but it's actually super easy. All you have to do is substitute a value for x and see what you get as the y value. The first thing I would do is rearrange the equation so that the equation is in the format y = something. So the first thing you should do is subtract 6x from both sides of the equation and you should get -y=-6x+9. Right now, the y is being multiplied by -1, and to undo multiplication, you have to divide. So divide both sides of the equation by -1 (remember, what you do on one side of the equation, YOU HAVE TO DO THE SAME THING ON THE OTHER SIDE). So your new equation would be y=6x-9. Then, all you have to do is substitute a value for x and see what you get for y (x is basically the input and whatever you get for y is the output). S for example, let's say that x=0. So substitute a 0 in the equation wherever you see an x. So in this case, you would get y=(6x0)+9. Then you just simplify. So 6x0 is 0 and 0+9=9 So y=9

TO RECAP: Rearrange the equation so that the equation is in the format y = something. Then, input any number for x, and whatever you get for y is what you put in the brackets as your y value for your final answer.

Hope this helps!

Yuki888 [10]3 years ago
4 0

Answer:

Here are three ordered pairs

1. (0,-9)

2. (1.5,0)

3. (5,21)

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3 years ago
Please answer this correctly
ankoles [38]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Find the sum of the first 47 terms of the following series, to the nearest integer.
topjm [15]

Answer:

The sum of the first 47 terms of the given series = 6016

Step-by-step explanation:

Given the sequence

13, 18, 23, ...

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

18-13=5,\:\quad \:23-18=5

As the difference between all the adjacent terms is the same.

so

d=5

a_1=13

Arithmetic sequence sum formula

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

Put the values

d=5

a_1=13

n=47

=47\left(13+\frac{5\left(47-1\right)}{2}\right)

=47\left(13+\frac{5\left(47-1\right)}{2}\right)

=47\left(13+115\right)

=47\cdot \:128

=6016

Thus, the sum of the first 47 terms of the given series = 6016

8 0
3 years ago
22.5+7(n-34) simplified
Aneli [31]
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3 years ago
I need help with 21 22 23.
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Read 2 more answers
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