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s344n2d4d5 [400]
3 years ago
9

Is (x+4)^2equivalent to 2x^2+8x+8

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

(x+4)^{2} = x^{2}+8x+16

Step-by-step explanation:

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Which shows two expressions that are equivalent to (Negative 7) (Negative 15) (Negative 5)?
Zigmanuir [339]

Answer:

negative 8

Step-by-step explanation:

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Answer:

Point coordinates: (5,5)

Explanation:

Q = (1,4)

4 units to the right is the same as <em>x + 4</em>

1 unit up is the same as <em>y + 1</em>

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HELP BY FIVE MINUTES PLEASE
kati45 [8]
Those are adjacent angles. They equal 180 degrees. 

10x-20+6x+8= 180

16x-12=180

Add 12.

16x= 192

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George Box, a famous statistician, once said, "All models are wrong, but some are useful." What did George Box mean by this stat
oksano4ka [1.4K]

Answer:

a model is an estimate or approximation of a data set. In the real world, there are too many variables to know exactly what will happen. However, if a model is a good fit, then it can be used to make predictions about what will happen. With a useful model, a predicted value should be a good estimate of an observed value.

Step-by-step explanation:

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If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
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